6y^2+16y=6

Solution for 6y^2+16y=6 equation:

6y^2+16y=6

We move all terms to the left:

6y^2+16y-(6)=0

a = 6; b = 16; c = -6;
Δ = b2-4ac
Δ = 162-4·6·(-6)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*6}=\frac{-36}{12}
=-3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*6}=\frac{4}{12}
=1/3
$